10 mL solution of `H_(2)SO_(4)` and `H_(2)C_(2)O_(4)` (oxalic acid), on titration with with 0.1 M KOH, required 20 " mL of " the base. 10 " mL of " the same solution on titration with `(M)/(300)K_(2)Cr_(2)O_(7)` required 50 " mL of " `K_(2)Cr_(2)O_(7)`.
Q. The strength of `H_(2)SO_(4)` is the solution is:

Options

A. `4.5gL^(-1)`
B. `4.9gL^(-1)`
C. `2.25gL^(-1)`
D. `2.45gL^(-1)`

Answer

B

Explanation

`m" Eq of "H_(2)SO_(4)(y)=1`
Weight of `H_(2)SO_(4)=1xx10^(-3)xx49` `(Ew of H_(2)SO_(4)=(98)/(2)=49)`
`=(0.049g)/(10mL)`
`=(0.049xx1000)/(10)gL^(-1)`
Therefore, the strength of `H_(2)SO_(4)=4.9gL^(-1)`