10 mL solution of `H_(2)SO_(4)` and `H_(2)C_(2)O_(4)` (oxalic acid), on titration with with 0.1 M KOH, required 20 " mL of " the base. 10 " mL of " the same solution on titration with `(M)/(300)K_(2)Cr_(2)O_(7)` required 50 " mL of " `K_(2)Cr_(2)O_(7)`.
Q. What should be the volume strength of `H_(2)Cr_(2)O_(7)`, if `H_(2)O_(2)` react with the same volume of `(M)/(300)K_(2)Cr_(2)O_(7)` solution.

Options

A. 5.6 V
B. 0.56 V
C. 11.2 V
D. 1.12 V

Answer

B

Explanation

`m" Eq of "H_(2)O_(2)=m" Eq of "K_(2)Cr_(2)O_(7)`
`=(1 mEq)/(10mL)`
`=(1xx10^(-3)xx10^(3))/(10)EqL^(-1)=0.1N`
Volume the strength of `H_(2)O_(2)=0.1xx5.6=0.56V`