A 5.0 mL solution of `H_(2)O_(2)` liberates 1.27 g of iodine from an acidified KI solution. The percentage strenth of `H_(2)O_(2)` is

Options

A. 11.2
B. 5.6
C. 1.7
D. 3.4

Answer

D

Explanation

`H_(2)O_(2)-=KI-=I_(2)`
`m" Eq of "H_(2)O_(2)=5xxN`
`m" Eq of "I_(2)=(Weight)/(eW)xx1000`
`=(1.27)/(127)xx1000=10mEq`
`I_(2)=Mw=254`
`Ew=(Mw)/(2)=(254)/(2)=127`
`thereforem " Eq of "H_(2)O_(2)=m" Eq of "I_(2)`
`5xxN=10becauseN=2`
`1N of H_(2)O_(2)=1.7%H_(2)O_(2)`
`2 N of H_(2)O_(2)=3.4% H_(2)O_(2)`