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If 100 mL of acidified 2NH(2)O(2) is all...

If `100 mL` of acidified `2NH_(2)O_(2)` is allowed to react with `KMnO_(4)` solution till there is light tinge of purples colour, the volume of oxygen produced at `STP` is :

A

2.24 L

B

1.12 L

C

3.36 L

D

4.48 L

Text Solution

Verified by Experts

The correct Answer is:
A
Volume of `O_(2)` at STP`=100mLxx11.2` volume strength ltBrgt `=1120 " mL of " O_(2) at STP`
(Since `1N=5.6` volume strength, `2N=11.2` volume strength of `H_(2)O_(2))`
Volume of `O_(2)` produced by `H_(2)O_(2)=1120mL`
Same volume of `O_(2)` will be produced by `KMnO_(4)=1120mL`
Total volume of `O_(2)=2240mL=2.24L`
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