In a reaction, `4` mole of electrons are transferred to `1` mole of `HNO_(3)`, the possible product obtained due to reduction is:

Options

A. `0.5 " mol of "N_(2)`
B. `0.5 " mol of "N_(2)O`
C. `1 " mol of "NO_(2)`
D. `1 " mol of "NH_(3)`

Answer

B

Explanation

`undersetunderset(x=5)(1+x-6=0)(HNO_(3)^(ɵ)+4e^(-))to(1)/(2)underset(a)overset(+1xx2-2)(N_(2)O)` (Species with oxidation number `=+1 is N_(2)O`)
Change in oxidation number `=5-a=4impliesa=1`