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If equal volumes of 0.1 M KMnO(4) and 0....

If equal volumes of `0.1 M KMnO_(4)` and `0.1 M K_(2)Cr_(2)O_(7)` solutions are allowed to oxidise `Fe^(2+)` to `Fe^(3+)` in acidic medium, then `Fe^(2+)` oxidised will be:

A

More by `KMnO_(4)`

B

More by `K_(2)Cr_(3)O_(7)`

C

Equal in both cases

D

Can't be determined

Text Solution

Verified by Experts

The correct Answer is:
B

`5Fe^(2+)MnO_(4)^(ɵ)+8H^(o+)to5Fe^(3+)+4H_(2)O+Mn^(2+)`
`6Fe^(2+)+Cr_(2)^(2-)+14H^(o+)to6Fe^(3+)+7H_(2)O+2Cr^(3+)`
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