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10mL of H2O2 solution (volume strength =...

`10mL` of `H_2O_2` solution (volume strength `= x`) requires `10mL` of `N//0.56 MnO_4^(ɵ)` solution in acidic medium. Hence`x` is

A

`0.56`

B

`5.6`

C

`0.1`

D

10`

Text Solution

Verified by Experts

The correct Answer is:
D
`10xxN_(1)(H_(2)O_(2))-=10xx(N)/(0.56)MnO_(4)^(ɵ)`
`N_(1)(H_(2)O_(2))=(1)/(0.56)`
`x` volume `H_(2)O_(2)` has normality`=(x)/(5.6)`
`(x)/(5.6)=(1)/(0.56)impliesx=10`
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