3 " mol of "a mixture of `FeSO_(4)` and `Fe_(2)(SO_(4))_(3)` requried 100 " mL of " 2 M `KMnO_(4)` solution in acidic medium. Hence, mole fraction of `FeSO_(4)` in the mixture is

Options

A. `(1)/(3)`
B. `(2)/(3)`
C. `(2)/(5)`
D. `(3)/(5)`

Answer

D

Explanation

`FeSO_(4)+Fe_(2)(SO_(4))_(3)+KMnO_(4)overset(H^(o+))to`
Only `FeSO_(4)` will be oxidised by `KMnO_(4)`
`m" Eq of "FeSO_(4)-=m" Eq of "KMnO_(4)`
`=2xx5xx100=1000`
`mEw of FeSO_(4)=1=" mol of "FeSO_(4)`
`Fe^(2+)toFe^(3+)+e^(-)`
`impliesx_(FeSO_(4))=(1)/(3)`