For the reaction
`M^(x+)+MnO_(4)^(ө)rarrMO_(3)^(ө)+Mn^(2+)+(1//2)O_(2)`
if `1 "mol of" MnO_(4)^(ө)` oxidises `1.67 "mol of" M^(x+) "to" MO_(3)^(ө)`, then the value of `x` in the reaction is

Options

A. 2
B. 3
C. 4
D. 5

Answer

A

Explanation

`M^(x+)+MnO_(4)^(ɵ)toMO_(3)^(ɵ)+Mn^(2+)`
`MnO_(4)^(ɵ)+8H^(o+)+5e^(-)toMn^(2+)+4H_(2)O`
`M^(x+)+3H_(2)OtoMO_(3)^(ɵ)+6H^(o+)+(5-x)e^(-)`
`m" Eq of "MnO_(4)^(2-)-=m" Eq of "M^(x+)`
`1xx5-=[1.67xx(5-x)]implies5-x=3impliesx=2`