`K_(2)Cr_(2)O_(7)` is obtained in the following steps:
`2FeCrO_(4)+2Na_(2)CO_(3)+OtoFe_(2)O_(3)+2Na_(2)CrO_(4)+2CO_(2)`
`2Na_(2)CrO_(4)+H_(2)SO_(4)toNa_(2)Cr_(2)O_(7)+H_(2)O+Na_(2)SO_(4)`
`Na_(2)Cr_(2)O_(7)+2KCltoK_(2)Cr_(2)+2NaCl`
To get 0.25 " mol of "`K_(2)Cr_(2)O_(7)`, " mol of "`50%` pure `FeCrO_(4)` required.

Options

A. 1 mol
B. 0.50 mol
C. 0.25 mol
D. 0.125 mol

Answer

A

Explanation

1 mol `K_(2)Cr_(2)O_(7)` is obtained from 2 " mol of "`FeCrO_(4)`
0.25 mol `K_(2)Cr_(2)O_(7)` is obtained from
`-0.50 " mol of "FeCrO_(4) (100%` pure)
`=1.00 mol (if 50%` pure)