The equivalent weight of `MnSO_(4)` is half its molecular weight when it is converted to

Options

A. `Mn_(2)O_(3)`
B. `MnO_(2)`
C. `MnO_(4)^(ɵ)`
D. `MnO_(4)^(2-)`

Answer

B

Explanation

`MnSO_(4)`
`x+6-8=0, x=2`
In (a) `Mn_(2)O_(3), 2x-6=0, x=3`
in (b) `MnO_(2), x-4=0, x=4`
In (c) `MnO_(4)^(ɵ), x-8=-1,x=7`
In (d) `MnO_(4)^(2-), x-8=-2,x=6`
In (b), the change in oxidation number is `4-2=2` Therefore, the answer is (b).