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What volume of 0.2 M KMnO(4) is required...

What volume of 0.2 M `KMnO_(4)` is required to react with 1.58 g of hypo solution `(Na_(2)S_(2)O_(3))` in acidc medium?

A

20 mL

B

10 mL

C

16.6 mL

D

50 mL

Text Solution

Verified by Experts

The correct Answer is:
B
Ew of `Na_(2)S_(2)O_(3)=(158)/(n)(n=1)`
`2S_(2)O_(3)^(2-)toS_(4)O_(6)^(2-)+2e^(-)(n=(2)/(2)=1)` ltBrgt `MnO_(4)^(ɵ)=S_(2)O_(3)^(2-)`
`mEw-=mEq`
`0.2 Mxx5` ("n-factor") `xxV=(1.58)/(158)xx10^(3)`
`V=10mL`
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