The weight of `MnO_(2)` and the volume of HCl of specific gravity 1.2 g `mL^(-1)` and `4%` nature by weight, needed to produce 1.78 L of `Cl_(2)` at STP. The reaction involved is:
`MnO_(2)+4"HCl"toMnCl_(2)+2H_(2)O+Cl_(2)`

Options

A. `0.48 L`
B. `0.24 L`
C. `0.12 L`
D. `0.06 L`

Answer

B

Explanation

`MnO_(2)+4"HCl"toMnCl_(2)+2H_(2)O+Cl_(2)`
`impliesW_(MnO_(2))=0.08xx97g=6.96g`,
`((10xx4xx1.2)/(36.5))xxV_(L)=0.32impliesV_(L)=0.24L`