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How many moles of O(2) will be liberated...

How many moles of `O_(2)` will be liberated by one mole of `CrO_(5)` is the following reaction:
`CrO_(5) + H_(2) SO_(4) rarr Cr_(2) (SO_(4))_(3) + H_(2)O + O_(2)`

A

`(5)/(2)`

B

`(5)/(4)`

C

`(9)/(2)`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
D
Balance the reaction:
`2CrO_(5)+3H_(2)SO_(4)toCr_(2)(SO_(4))_(3)+2H_(2)O+(7)/(2)O_(2)`
`implies1 mol CrO_(5)` liberated `(7)/(2)` mol `O_(2)`
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How many moles of O_(2) will be liberated by one mole of CrO_(5) is the following reaction: CrO_(5) + H_(2) SO_(4) rarr Cr_(2) (SO_(4))_(5) + H_(2)O + O_(2)

In a balanced redox reaction net gain of electron (s) is equal to net loss of electrons (s). n_("factor") is a reaction specific parameter and for intermolecular redox reaction n-factor of oxidising reducing agent is the no. of moles of electron gained /lost by one mole of compound. Consider the following reaction: CrO_(5)+H_(2)SO_(4) to Cr_(2)(SO_(4))_(3)+H_(2)O+O_(2) One mole of CrO_(5) will liberate how many moles of O_(2) ?

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