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2.25 dm^(3) of chlorine at 283 K is heat...

`2.25 dm^(3)` of chlorine at 283 K is heated until the volume becomes `30 dm^(3)`. To what temperature the gas must be raised to accomplish the change ?

Text Solution

Verified by Experts

Given
`V_(1)=2.25dm^(3)`
`T_(1)=283K`
`V_(2)=30dm^(3)`
`T_(2)=?`
`thereforeT_(2)=V_(2)T_(1)//V_(1)=3773.3K`
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