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The molar volumes of KCl and NaCl are 40...

The molar volumes of `KCl` and `NaCl` are `40 mL` and `30 mL`, respectively. Find the ratio of the unit cube edges of the two crystals. Assume both have the same packing efficiency.

Text Solution

Verified by Experts

Since both `KCl` and `NaCl` have `fc c`-type arrangement, therefore, `Z_(eff)` for both `KCl` and `NaCl = 4`/unit cell
Moreover, packing efficiency of both are same.
Hence,
`(a_(KCl)^(3))/(a_(NaCl)^(3)) = ("Volume of unit cell of" KCl)/ ("Volume of unit cell of" NaCl)`
`:. a_(KCl)/a_(NaCl) = ((40)/(30))^((1)/(3) = 1.113`
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