In the cubic crystal of `CsCl (d = 3.97 g cm^(-3))`, the eight corners are occupied by `Cl^(Θ)` with a `Cs^(o+)` at the centre and vice versa. Calculate the distance between the neighbouring `Cs^(o+)` and `Cl^(Θ)` ions. What is the radius of the two ions? (`Aw` of `Cs = 132.91` and `Cl = 35.45)`

Explanation

To solve the problem, we will follow these steps:

### Step 1: Calculate the Molecular Mass of CsCl
The molecular mass (M) of CsCl can be calculated using the atomic masses provided:
- Atomic mass of Cs = 132.91 g/mol
- Atomic mass of Cl = 35.45 g/mol

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