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Li forms a body-centred cubic lattice. I...

`Li` forms a body-centred cubic lattice. If the edge of the cube is `3.5 xx 10^(-10)m` and the density is `5.3 xx 10^(2) kg m^(-3)`, calculate the percentage occupancy of `Li` metal.

Text Solution

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`= (Z_(eff) xx Aw)/(N_(A) xx a^(3)) = (2 xx 7 xx 10^(-3))/(6.023 xx 10^(23) xx (3.5 xx 10^(10))^(3))`
`= 5.4 xx 10^(2) kg m^(-3)`
Percentage occupancy `= (5.3 xx 10^(2))/(5.4 xx 10^(2)) xx 100 = 98%`
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