A solution of sucrose (molar mass =342) is prepared by dissolving 688.4 g in 1000 g of water. Calculate
The freezing point of solution.

Options

A. `273`
B. `373`
C. `272.628`
D. `271.628`

Answer

C

Explanation

Freezing point of solution can be calculated by using the relation
`DeltaT_(f)=(K_(f) xx 1000 xx W_(B))/(W_(A) xx Mw_(B))`
`K_(f)=1.86 K m^(-1)`
`:. Delta T_(f)=(1.86 xx 1000 xx68.4)/(1000 xx 342)=0.372`
Freezing point fo solution
=Freezing point of pure water -`DeltaT_(f)`
=273-0.372=272.628 K