Osmotic pressure of `40%` (wt.`//`vol.) urea solution is `1.64 atm` and that of `3.42%` (wt.`//`vol.) cane sugar is `2.46 atm`. When equal volumes of the above two solutions are mixed, the osmotic pressure of the resulting solution is:

Options

A. `1.64 atm`
B. `2.46 atm`
C. `4.10 atm`
D. `2.05 atm`

Answer

D

Explanation

`pi=(pi_(1) + pi_(2))/2`, if equal volumes are mixed,volume of solution becomes double.