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The molal elevation constant of water =0...

The molal elevation constant of water =`0.52 K m^(-1)`. The boiling point of `1.0 molal` aqueous `KCl` solution (assuming complete dissociation of `KCl`) should be

A

`100.52^(@)C`

B

`101.04^(@)C`

C

`99.48^(@)C`

D

`98.96^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
B
`DeltaT_(b)=K_(b) xx m=0.52 xx 1 xx 2 =1.04`,
`:. T_(b)=100 + 1.04 =101.04^(@)C`
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