At `40^(@)C` the vapour pressure of pure liquids, benzene and toluene, are `160 mm Hg` and `60 mm Hg` respectively. At the same temperature, the vapour pressure of an equimolar solution of the liquids, assuming the ideal solution will be:

Options

A. `140 mm Hg`
B. `110 mm Hg`
C. `220 mm Hg`
D. `100 mm Hg`

Answer

B

Explanation

`P_(m)=160 xx 1/2 +60 xx 1/2 =100 mm`