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The mole fraction of toluene in the vapo...

The mole fraction of toluene in the vapour phase which is in equilibrium with a solution of benzene `(P_(B)^(@)=120 "torr")` and toluene `(P_(T)^(@)=80 "torr")` having `2.0 mol` of each, is

A

0.5

B

0.25

C

0.6

D

0.4

Text Solution

Verified by Experts

The correct Answer is:
D
`chi'_(T)(vap) =(chi_(T)P_(T)^(@))/(chi_(T)P_(T)^(@) + chi_(B)P_(B)^(@))`
`=0.4`
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