When mercuric iodide is added to the aqueous solution of potassium iodide, then:

Options

A. Freezing point is raised.
B. Freezing point is lowered.
C. Freezing point does not change.
D. Boiling point does not change.

Answer

A

Explanation

During complex formation, more number of particles join to form a larger particles which does not break. So the particle number is reduced and the freezing point is elevated.
`2Kl+Hgl_2hArrK_2Hgl_4`
`K_2[HgI_4]hArr2K^(o+)+Hfl_4^(2-)`