Home
Class 12
CHEMISTRY
An aqueous solution containing an ionic ...

An aqueous solution containing an ionic salt having molality equal to `0.19` freezes at `-0.704^(@)C`. The Van't Hoff factor of the ionic salt is (`K_(f)` for water=`1.86 K m^(-1)`)

A

3

B

2

C

4

D

5

Text Solution

Verified by Experts

The correct Answer is:
B

`DeltaT_(f)=iK_(f)m rArr 0.704 = I xx 1.86 xx 0.19 rArr i=2`
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    CENGAGE CHEMISTRY|Exercise Ex 2.2 (Objective)|9 Videos
  • SOLID STATE

    CENGAGE CHEMISTRY|Exercise Ex 1.2 (Objective)|9 Videos
  • SURFACE CHEMISTRY

    CENGAGE CHEMISTRY|Exercise Archives Subjective|2 Videos

Similar Questions

Explore conceptually related problems

Calculate the freezing point depression expected for 0.0711 m aqueous solution of Na_(2)SO_(4) . If this solution actually freezes at -0.320 ^(@)C , what would be the value of Van't Hoff factor ? ( K_(f) for water is 1.86 ^(@)C mol^(-1) ) .

A 0.5% aqueous solution of KCl was found to freeze at -0.24^(@)C . Calculate the Van,t Hoff factor and degree of dissociation of the solute at this concentration. ( K_(f) for water = 1.86 K kg mol ^(-1) )

A solution containing 6.8 g of non-ionic solute in 100g of water was found to freeze at -0.93^(@)C . If K_(f) for water is 1.86, the mol. Mass of solute is

0.15 molal solution of NaCI has freezing point -0.52 ^(@)C Calculate van't Hoff factor . (K_(f) = 1.86 K kg mol^(-1) )