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The compressibility factor (Z=PV//nRT) f...

The compressibility factor `(Z=PV//nRT)` for `N_(2)` at `223 K` and `81.06 MPa` is `1.95`, and at `373 K` and `20.265 MPa`, it is `1.10`. A certain mass of `N_(2)` occupies a volume of `1.0 dm^(3)` at `223 K` and `81.06 MPa`. Calculate the volume occupied by the same quantity of `N_(2)` at `373 K` and `20.265 MPa`.

A

`3.774 dm^(3)`

B

`2.77 dm^(3)`

C

`5.07 dm^(3)`

D

`9.30 dm^(3)`

Text Solution

Verified by Experts

The correct Answer is:
A

For T = 223 K, P = 81.06 Mpa, Z = 1.95, and `V=1.0 dm^(3)=10^(3)cm^(3)`, we have
`n=(PV)/(ZRT)=(81.06xx10^(3))/(1.95xx8.314xx223)=22.42` mol
Now, at T = 373 K, P = 20,265 Mpa, Z = 1.10, the volume occupied will be
`V=(ZnRT)/(P)=(1.10xx22.42xx8.314xx373)/(20.265)=3774.0 cm^(3)`
`therefore V=3.774 dm^(3)`
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