Home
Class 11
PHYSICS
The friction of the air causes a vertica...

The friction of the air causes a vertical retardation equal to 10% of the acceleration due to gravity `(take g=10ms^(-2))` The maximum height will be decreased by:

Text Solution

Verified by Experts

`T = (2 u sin theta)/(g) therefore (T_1)/(T_2) = (g_2)/(g_1) = (g + (g)/(10))/(g) = (11)/(10)`
Fractional decrease in time of flight `= (T_1 - T_2)/(T_1) = (1)/(11)`
Percantage decrease `= 9 %`.
Promotional Banner

Topper's Solved these Questions

  • KINEMATICS-2

    CENGAGE PHYSICS|Exercise Exercise 5.2|25 Videos

  • KINEMATICS-2

    CENGAGE PHYSICS|Exercise Exercise 5.3|12 Videos

  • KINEMATICS-2

    CENGAGE PHYSICS|Exercise Solved Examples|7 Videos

  • KINEMATICS-1

    CENGAGE PHYSICS|Exercise Integer|9 Videos

  • KINETIC THEORY OF GASES

    CENGAGE PHYSICS|Exercise Compression|2 Videos

Similar Questions

Explore conceptually related problems

The friction of the air causes a vertical retardation equal to 10% of the acceleration due to gravity. Take g=10 m//s^(2) the maximum height and time to reach the maximum height will be decreased by

Acceleration the due to gravity become [(g)/(2)] at a height equal to

Taking the value of the acceleration due toj gravity as 10 m s^(-2) , Find its value in km h^(-2).

What is the value of the acceleration due to gravity at a height equal to radius of earth?

The acceleration of block is( g=10 ms-2)

Spot the correct statements : The acceleration due to gravity 'g' decreases if

At a height equal to earth's radius, above the earth's surface, the acceleration due to gravity is

If radius of earth decreases by 10%, then acceleration due to gravity (Density of earth remain constant)

Spot the wrong statement : The acceleration due to gravity ‘ g ’ decreases if