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A boy playing on the roof of a 10 m high...

A boy playing on the roof of a `10 m` high building throws a ball with a speed of `10 m//s` at an angle of `30(@)` with the horizontal. How far from the throwing point will the ball be at the height of `10 m` from the ground ?
`[ g = 10m//s^(2) , sin 30^(@) = (1)/(2) , cos 30^(@) = (sqrt(3))/(2)]`

Text Solution

Verified by Experts

We have to simply calculate the range of projectile.
`R = (u^2 sin 2 theta)/(g) = ((10)^2 sin (2 xx 30^@))/(10)`
=`s sqrt(3) = 8.66 m`.
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