A box of mass 8 kg placed on a rough in...

A box of mass `8 kg ` placed on a rough inclined plane of inclened `theta` its downward motion can be prevented by applying an upward pull `F` and it can be made to slide upward appliying a force `2F` .The coefficient of friction between the box and the inclined plane is

`(tan theta)//3`

`3 tan theta`

`(tan theta)//2`

`2 tan theta`

Text Solution

Verified by Experts

The correct Answer is:

During downward motion
`F = mg sin theta - mg cos theta`
During upward motion
`2F = mg sin theta + mu mg cos theta`
Solving above two equation we get `m = (tan theta)//3`

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