A block of mass `15 kg` is resting on a rough inclined plane as shown in figure ,The block is tied by a horizontal string which has a tension `50 N` The coefficient of contact is

Options

A. `1//2`
B. `2//3`
C. `3//4`
D. `1//4`

Answer

A

Explanation

The string is under tension Hence there is limiting friction between the block and the plane

`sumF_(x) = 0 rArr mu N + 50 cos 45^(@) = 150 sin 45^(@)`…(I)
`sumF_(y) = 0 rArr N = 50 cos 45^(@) = 150 sin 45^(@)`…(iI)
Solving Eqs (i) and (ii) we get `m = 1//2`