In figure the tension in the rope (rope is light) is

Options

A. `(M + m) g sin theta`
B. `(M + m) g sin theta - mu mg cos theta`
C. Zero
D. `(M + m) g sin theta`

Answer

c

Explanation

`N_(1) = mg cos theta and f_(1) = mu mg cos theta`

` N_(2) = Mg cos theta and f_(2) = mu Mg cos theta `
Equation of motion are
`T - f_(1) + mg sin theta = ma`…(i)
`Mg sin theta - T - f_(2) = Ma`….(ii)
Solving Eqs (i) and (ii) we get `T = 0`