The system is pushed by a force F as shown in figure All surface are smooth except between B and C friction coefficient between B and C is Minimum value of F to prevent block B from down ward slipping is

Options

A. `((3)/(2 mu))mg`
B. `((5)/(2 mu))mg`
C. `((5)/(2))mu mg`
D. `((3)/(2))mu mg`

Answer

b

Explanation

Horizontal acceleration of the system is
`a = (F)/(2m + m+ 2m) = (F)/(2m)`
Let `N` be the normal reaction between B and C free body diagram of `C` gives
ltBRgt `n = 2 MA = (2)/(5)f`
Now B will not slide downward if
`muN ge m_(B)g`
or `mu((2)/(5) f) ge mg` or `F ge (5)/(2mu) mg`
so `F_(min) = (5)/(2 mu)mg`