Figure shown a wooden block at rest in equilibrium on a rought horizontal plane being acted upon by force `F_(1) = 10 N, F_(2) = 2 N`, as shown .IF`F_(1)` is removed , the resulting force acting on the block will be

Options

A. `2 N` toward left
B. `2 N` toward right
C. `0 N`
D. cannot be determined

Answer

c

Explanation

The driving force on the block

`F_(1) - F_(2) = 10 - 2 = 8 N`
As the block is at rest the friction will be static and toward left
`f = f_(1) = 8 N`
If `F_(1)` is removed only `f_(2) = 2 N` is acting on the block

If the block is at rest `f = F_(2) = 2N` this value of friction is within static range as in previous case even `f= 8 N` is staic case