A block is resting over a rough horizontal floor. At `t = 0` a time -verying force starts acting on it , the force is described by equation `F = kt` where k is constant and r is in seconds Marks the cerrect statement (s) for this situation .

Options

A. Curve 1 showns acceleration - time graph
B. Curve 2 showns acceleration - time graph
C. Curve 3 showns velocity - time graph
D. Curve 4 showns displacement - time graph

Answer

b

Explanation

For some time, block would not move due to friction force when `F lt f_(2)` the motion of block starts

` a = (F - f_(k))/(m) = (kt - f_(k))/(m)`
`rArr (dv)/(dt) = a = (kt - f_(k))/(m)`
`v = ((kt^(2))/(2)- (f_(k)t))/(m)`
`rArr (dx)/(dt) = ((kt^(2))/(2)- f_(k)t)/(m) rArr x = ((kt^(2))/(6) - f_(k)t^(2)/(2))/(m)`