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A long conveyer belt moves with a consta...

A long conveyer belt moves with a constant velocity of `8 ms^(-1)`.Two blockA and B each of mass `2kg` are placed gently on the belt with B on A, initail velocity of block is zero Coefficient of friction between A and belt is `0.1` There is no friction between A and B length of A is `4m`

Find the velocity of A when B falls off A

A

`2ms^(-1)`

B

`4ms^(-1)`

C

`6ms^(-1)`

D

`8ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
b
`v_(A) = u + at = 0 + 2xx2= 4 ms^(-1)`
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