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A composite rod comprising two rods of m...

A composite rod comprising two rods of mass `m` and `2m` and each of length `l = 1 m` as shown in the figure. Assume `omega = 10 rad//s` and `m = 1 kg`, the `KE` of the rotating composite rod is.
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Text Solution

Verified by Experts

Moment of inertia of composite rod about P

`I_(P)=(ml^(2))/3+((2m)^(2))/12+2m(3/2l)^(2)=5ml^(2)`
total kinetic energy `k_("total")=I_(P)omega^(2)`
`=1/2(5ml^(2))omega^(2)=5/2ml^(2)omega^(2)=250J`
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