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In moving from A to B along an electric ...

In moving from A to B along an electric field line, the work done by the electric field on an electron is `6.4 xx 10^-19 J`. If `phi_1 and phi_2` are equipotential surfaces, then the potential difference `V_C - V_A ` is.
.

A

`-4 V`

B

`4 V`

C

zero

D

`6.4 V`

Text Solution

Verified by Experts

The correct Answer is:
B
`W_(e 1.) = q(V_i - V_f)`
or `6.4 xx 10^-19 = -1.6 xx 10^-19 (V_A - V_B)`
or `V_A - V_B = -4 V`
or `V_A - V_C = -4 V ( because V_B = V_C)`
or `V_C - V_A = 4 V`.
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