(Figure 3.139) shows three circular arcs, each of radius `R` and total charge as indicated. The net electric potential at the center of curvature.
.

Options

A. `q/(2 pi epsilon_0 R)`
B. `(5 Q)/(12 pi epsilon_0 R)`
C. `(3 Q)/(32 pi epsilon_0 R)`
D. none of these.

Answer

a

Explanation

Charge can be considered as located at a distance `R` from the center. Total charge is `(Q - 2 Q+ 3Q) = 2 Q`
Hence, `V = (1)/(4 pi epsilon_0) (2 Q)/r = Q/(2 pi epsilon_0 R)`.