A particle performs simple hormonic motion with a period of 2 seconds. The time taken by it to cover a displacement equal to half of its amplitude from the mean position is

Options

A. `1//2 sec`
B. `1//3 sec`
C. `1//4 sec`
D. `1//6 sec`

Answer

D

Explanation

`x= A sin t(2 pi)/(T)`, for `x = (A)/(2) rArr (A)/(2) = A sin (2pi)/(T)t`
Solving `x = (T)/(6)`