The phase difference between two particle executing `SHM` of the same amplitude and frequency along same straight line while pessing one another when going in apposition direction with equal displacement from then respectively straing about is is `2pi//3` if the prass if one particle is `pi//6` find the displecement at this instant amplitude is `A`

Options

A. `A//3`
B. `2A//3`
C. `3A//4`
D. `A//2`

Answer

D

Explanation

Phase difference `delta = (2pi)/(3) = delta_(2)- delta_(1) = delta_(2)`
`= delta_(2) - (pi)/(6) rArr delta_(2) - (5pi)/(6), sin delta_(1) = sin delta_(2) = (1)/(2)`
Displacement is measured from starting, point `(t = 0)`
So, `s = A sin(omega t + delta_(1)), A sin (0 + (pi)/(6)) = (A)/(2)`