Two pandulums have time period `T` and `(5T)/(4)`. They `S.H.M.` at the same time from after the bigger pendulum has camplates one oscillation ?

Options

A. `45^(@)`
B. `90^(@)`
C. `60^(@)`
D. `30^(@)`

Answer

B

Explanation

`(5T)/(4)= T + (T)/(4)`

By the time , the bigger perdulum makes full oscilation, the smaller pendulum will make `(1 + (1)/(4))` osclillation The biggerpendulum will be in the mean position and the smaller one will be in the position extreme position Thus phase difference `= 90^(@)`