In the above question the mass of the particle is

Options

A. `3 pi^(2)`
B. `(5 pi^(2))/(4)`
C. `(5)/(4 pi^(2))`
D. `(1)/(3pi^(2))`

Answer

C

Explanation

From above question
`omega = 2 pi rArr T = (2pi)/(omega) = 1 sec`
`Also T = 2pi sqrt((m)/(k)) rArr m = (T^(2)k)/(4 pi^(2)) = (1 xx 5)/(4 pi^(2)) = (5)/(4pi^(2))`