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A particle moves along a straight line t...

A particle moves along a straight line to follow the equation `ax^(2) + bv^(2) = k`, where `a, b` is and k are constant and `x` and and `x` axis coordirete and velocity of the particle respectively find the amplitude

A

`sqrt((k)/(b))`

B

`sqrt((b)/(k))`

C

`sqrt((a)/(k))`

D

`sqrt((g)/(a))`

Text Solution

Verified by Experts

The correct Answer is:
D

`ax^(2) + bv^(2) = k`
`hv^(2) = k - ax^(2)`
`v^(2) = (k)/(b) - (a)/(b) x^(2)`
Compare with `v^(2) = A^(2) omega^(2) - omega^(2)x^(2)`
`omega^(2) = d//b` and `A^(2)omega^(2) = k//b`
`A = sqrt((A^(2) omega^(2))/(omega^(2)) = sqrt((k//b)/(a//b)) = sqrt((k)/(a))`
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