The time period of oscillation of a bar magnet suspended horizontaliy along the magnetic meridian is `T_(0)`. If this magnet is replaced by another magnet of the same size and pole strength but with double the mass, the new time period will be

Options

A. `T_(0)/2`
B. `T_(0)/sqrt(2)`
C. `sqrt(2)T_(0)`
D. `2T_(0)`

Answer

C

Explanation

`T=2pi sqrt(I/(MB_(H)))impliesT prop sqrt(I) prop sqrt(w) implies T^(')=sqrt(2)T_(0)`