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A magnetic needle is made to vibrate in ...

A magnetic needle is made to vibrate in uniform field `H`, then its time period is `T`. If it vibrates in the field of intensity `4H`, its time period will be

A

`2T`

B

`T//2`

C

`2//T`

D

`T`

Text Solution

Verified by Experts

The correct Answer is:
B
`T= 2pisqrt(I/(MB_(H))) impliesT_(1)/T_(2)= sqrt((B_(H))_(2)/((B_(H))_(1)))`
`implies T_(2)=Tsqrt((BH)_(1)/((BH)_(2)))=T/2 ( :' (B_(H))_(2)=4(B_(H))_(1))`
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