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A magnet of magnetic moment M oscillatin...

A magnet of magnetic moment `M` oscillating freely in earth's horizontal magnetic field makes n oscillations per minute. If the magnetic moment is quadrupled and the earth's field is doubled, the number of oscillations mode per minute would be

A

`n/(2sqrt(2))`

B

`n/sqrt(2)`

C

`2sqrt(2n)`

D

`sqrt(2n)`

Text Solution

Verified by Experts

The correct Answer is:
C
No. of oscillation per minute `=1/(2pi)sqrt((MB_(H))/I)`
`implies n prop sqrt(MB_(H)), Mrarr4 "times"`
`B_(H)rarr2` "times"`
So `vrarr sqrt(8) "times" i.e. v^(')=sqrt(8)v=2sqrt(2)n`
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Knowledge Check

  • When a bar magnet is placed at some distance along the axis of the magnetic needle of an oscillation magnetometer located in earth's magnetic field, the needle makes 14 oscillaitons per minute. If the bar magnet is turned so that its poles exchange their positions, the needle makes 20 oscillations per minute. If the magnet is completely removed, the frequency of the needle is nearly ("assuming"BgtB_(H) "at needle")

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