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A magnet of magnetic moment M oscillatin...

A magnet of magnetic moment `M` oscillating freely in earth's horizontal magnetic field makes n oscillations per minute. If the magnetic moment is quadrupled and the earth's field is doubled, the number of oscillations mode per minute would be

A

`n/(2sqrt(2))`

B

`n/sqrt(2)`

C

`2sqrt(2n)`

D

`sqrt(2n)`

Text Solution

Verified by Experts

The correct Answer is:
C
No. of oscillation per minute `=1/(2pi)sqrt((MB_(H))/I)`
`implies n prop sqrt(MB_(H)), Mrarr4 "times"`
`B_(H)rarr2` "times"`
So `vrarr sqrt(8) "times" i.e. v^(')=sqrt(8)v=2sqrt(2)n`
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