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A magnet oscillating in a horizontal pla...

A magnet oscillating in a horizontal plane has a time period of 2 seconds at a place where the angle of dip is `30^(@)` and 3 seconds at another place where the angle of dip is `60^(@)`. The retio of resultant magnetic field at the two places is

A

`(4sqrt(3))/7`

B

`4/(9sqrt(3))`

C

`4/(4sqrt(3))`

D

`9/sqrt(3)`

Text Solution

Verified by Experts

The correct Answer is:
C

`T prop 1/sqrt(B_(H))=1/sqrt(B cos varphi)implies T_(1)/T_(2)=sqrt((B_(2) cos varphi_(2))/(B_(2) cos varphi_(1)))`
`impliesB_(1)/B_(2)=T_(2)^(2)/T_(1)^(2)xx(cos varphi_(2))/(cos varphi_(1))=(3/2)^(2)xx(cos 60)/(cos 30)implies B_(1)/B_(2)=9/(4sqrt(3))`
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