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A bar magnet is oscillating in the earth...

A bar magnet is oscillating in the earth's magnetic field with a period T. What happens to its period and motion if its mass is quadrupled

A

Motion remains S.H.M. with time period =2T

B

Motion remains S.H.M. with time period =`4T`

C

Motion remains S.H.M. and period remains nearly constant

D

Motion remains S.H.M. with time period =`T/2`

Text Solution

Verified by Experts

The correct Answer is:
A

As `T prop sqrt(I)`, where I= moment of inertia
`=(wL^(2))/12impliesTpropsqrt(w)` (w= Mass of magnet. If wrarr quadrupled, then Trarr doubled, i.e., `T^(')=2T`
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Knowledge Check

  • A bar magnet is osciallating in the earth's magnetic field with a period T. What happens to its period of motion of its mass is quad-rupled without changing its dimensions?

    A
    Motion remains SHM with period `=T//2`
    B
    Motion remains SHM with period `=2T`
    C
    Motion remains SHM with period `=4T`
    D
    Motion is not SHM, but period `=T`
  • A bar magnet is oscillating in the earth's magnetic field with a time period T . If the mass is quadrupled, then its time period will be:

    A
    `T//2`
    B
    `T`
    C
    `2T`
    D
    `4T`
  • A bar magnet is oscillating in the earth's magnetic field with a time period T . If the mass is increased four times, then its time period will be:

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    B
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    D
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