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Two identical bar magnets are placed on above the other such that they are mutually perpendicular and bisect each other. The time period of this combination in a horizontal magnetic field is T. The time period of esch magnet in the same field is

A

`sqrt(2)T`

B

`2^(1/4)T`

C

`2^(-1/4)T`

D

`2^(-1/2)T`

Text Solution

Verified by Experts

The correct Answer is:
C

Time period of a combination

`T=2pisqrt((2I)/(sqrt(2)M.H)) ...(i)`
and time period of each magnet
`T^(')=2pisqrt(I/(MH)) ...(ii)`
from (i) and (ii) we get
`T^(')=T/2^(1//4)=2^(-1//4)T`
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