When a p-n junction diode is reverse biased

Options

A. no current flows
B. the depletion region is increased
C. the depletion reagion is reduced
D. the height of the potential barrier is reduced

Answer

b

Explanation

In reverse biasing, the applied voltage`V` on the `n-` side is positive and is negative on the `p-`side. The applied bias `V` and the barrier potential `V_(B)` are in the same direction making the effective junction potential `V+V_(B)`. As a result, the junction width will increase. The higher junction potential would restrict the flow of majority carriers to a much greater extent. However, such a field will favour the flow of minority carriers. So, reverse bias current will be due to the minority carriers only.